JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
Two billiard balls of equal mass \(30 \,{g}\) strike a rigid wall with same speed of \(108\, {kmph}\) (as shown) but at different angles. If the balls get reflected with the same speed then the ratio of the magnitude of impulses imparted to ball \('a'\) and ball \('b'\) by the wall along \('X'\) direction is :

- A \(1: 1\)
- B \(\sqrt{2}: 1\)
- C \(1: \sqrt{2}\)
- D \(2: 1\)
Answer & Solution
Correct Answer
(B) \(\sqrt{2}: 1\)
Step-by-step Solution
Detailed explanation
Ball (a) \(|\overrightarrow{\Delta p }|=2 mu = J _{1}\) Ball (b) \(|\overrightarrow{\Delta p }|=2 mu \cos 45^{\circ}= J _{2}\) \(\frac{J_{1}}{J_{2}}=\frac{1}{\cos 45^{\circ}}=\sqrt{2}\)
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