JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
An object is placed in a medium of refractive index \(3\). An electromagnetic wave of intensity \(6 \times 10^8 \mathrm{~W} / \mathrm{m}^2\) falls normally on the object and it is absorbed completely. The radiation pressure on the object would be (speed of light in free space \(=3 \times 10^8 \mathrm{~m} / \mathrm{s}\) ):
- A \(36\ \mathrm{Nm}^{-2}\)
- B \(18\ \mathrm{Nm}^{-2}\)
- C \(6 \ \mathrm{Nm}^{-2}\)
- D \(2\ \mathrm{Nm}^{-2}\)
Answer & Solution
Correct Answer
(C) \(6 \ \mathrm{Nm}^{-2}\)
Step-by-step Solution
Detailed explanation
\( \text { Radiation pressure }=\frac{I}{V} \) \( =\frac{I \cdot \mu}{c} \) \( =\frac{6 \times 10^8 \times 3}{3 \times 10^8} \) \( =6 \mathrm{~N} / \mathrm{m}^2\)
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