JEE Mains · Physics · STD 12 - 1. Electric charges and fields
Two identical charged particles each having a mass \(10 \,g\) and charge \(2.0 \times 10^{-7}\,C\) area placed on a horizontal table with a separation of \(L\) between then such that they stay in limited equilibrium. If the coefficient of friction between each particle and the table is \(0.25\), find the value of \(L\).[Use \(g =10\,ms ^{-2}\) ]..........\(cm\)
- A \(12\)
- B \(10\)
- C \(8\)
- D \(5\)
Answer & Solution
Correct Answer
(A) \(12\)
Step-by-step Solution
Detailed explanation
\(\frac{ kq ^{2}}{ L ^{2}}=\mu mg \Rightarrow L =\sqrt{\frac{ k }{\mu mg } q }\)
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