JEE Mains · Physics · STD 11 - 14. waves and sound
A uniform string oflength \(20\ m\) is suspended from a rigid support. A short wave pulse is introduced at its lowest end. It starts moving up the string. The time taken to reach the supports is (take \(g= 10 \) \(ms^{-2}\) )
- A \(2\)\(\sqrt 2 s\)
- B \(\sqrt 2 s\)
- C \(\;2\pi \sqrt 2 s\)
- D \(2s\)
Answer & Solution
Correct Answer
(A) \(2\)\(\sqrt 2 s\)
Step-by-step Solution
Detailed explanation
We know that velocity in string is given by \(\mathrm{v}=\sqrt{\frac{\mathrm{T}}{\mu}}\) \(...(I)\) where \(\mu=\frac{\mathrm{m}}{1}=\frac{\text { mass of string }}{\text { length of string }}\) The tension…
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