JEE Mains · Physics · STD 12 - 1. Electric charges and fields
A point charge causes an electric flux of \(-2 \times 10^4 \mathrm{Nm}^2 \mathrm{C}^{-1}\) to pass through a spherical Gaussian surface of 8.0 cm radius, centred on the charge. The value of the point charge is :
(Given \(\epsilon_0=8.85 \times 10^{-12} \mathrm{C}^2 \mathrm{~N}^{-1} \mathrm{~m}^{-2}\) )
- A \(15.7 \times 10^{-8} \mathrm{C}\)
- B \(17.7 \times 10^{-8} \mathrm{C}\)
- C \(-15.7 \times 10^{-8} \mathrm{C}\)
- D \(-17.7 \times 10^{-8} \mathrm{C}\)
Answer & Solution
Correct Answer
(D) \(-17.7 \times 10^{-8} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { Flux }(\phi)=\frac{\theta_{\text {inc }}}{\epsilon_0} \\ & \begin{aligned} \theta_{\text {inc }} & =\epsilon_0 \phi \\ \quad= & -17.7 \times 10^{-8} \mathrm{C}\end{aligned}\end{aligned}\)
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