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JEE Mains · Physics · STD 12 - 1. Electric charges and fields

A point charge causes an electric flux of \(-2 \times 10^4 \mathrm{Nm}^2 \mathrm{C}^{-1}\) to pass through a spherical Gaussian surface of 8.0 cm radius, centred on the charge. The value of the point charge is :
(Given \(\epsilon_0=8.85 \times 10^{-12} \mathrm{C}^2 \mathrm{~N}^{-1} \mathrm{~m}^{-2}\) )

  1. A \(15.7 \times 10^{-8} \mathrm{C}\)
  2. B \(17.7 \times 10^{-8} \mathrm{C}\)
  3. C \(-15.7 \times 10^{-8} \mathrm{C}\)
  4. D \(-17.7 \times 10^{-8} \mathrm{C}\)
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Answer & Solution

Correct Answer

(D) \(-17.7 \times 10^{-8} \mathrm{C}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \text { Flux }(\phi)=\frac{\theta_{\text {inc }}}{\epsilon_0} \\ & \begin{aligned} \theta_{\text {inc }} & =\epsilon_0 \phi \\ \quad= & -17.7 \times 10^{-8} \mathrm{C}\end{aligned}\end{aligned}\)
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