JEE Mains · Physics · STD 11 - Oscillations
- JEE Mains 2021
- Medium
- Numerical
Two simple harmonic motions are represented by the equations \({x}_{1}=5 \sin \left(2 \pi {t}+\frac{\pi}{4}\right)\) and \({x}_{2}=5 \sqrt{2}(\sin 2 \pi {t}+\cos 2 \pi {t})\) The amplitude of second motion is ....... times the amplitude in first motion.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
\({x}_{2}=5 \sqrt{2}\left(\frac{1}{\sqrt{2}} \sin 2 \pi {t}+\frac{1}{\sqrt{2}} \cos 2 \pi {t}\right) \sqrt{2}\)
\(=10 \sin \left(2 \pi {t}+\frac{\pi}{4}\right)\)
\(\therefore \frac{{A}_{2}}{{A}_{1}}=\frac{10}{5}=2\)
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