JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
A machine gun of mass \(10\,kg\) fires \(20\,g\) bullets at the rate of \(180\) bullets per minute with a speed of \(100\,m s ^{-1}\) each. The recoil velocity of the gun is \(.............\,m/s\)
- A \(0.02\)
- B \(2.5\)
- C \(1.5\)
- D \(0.6\)
Answer & Solution
Correct Answer
(D) \(0.6\)
Step-by-step Solution
Detailed explanation
\(20 \times 10^{-3} \times \frac{180}{60} \times 100=10\,V\) \(\Rightarrow v =0.6\,m / s\)
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