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JEE Mains · Physics · STD 11 - 13. oscillations

The point \(A\) moves with a uniform speed along the circumference of a circle of radius \(0.36\, m\) and covers \(30^{\circ}\) in \(0.1\, s\). The perpendicular projection \('P'\) from \('A'\) on the diameter \(MN\) represents the simple harmonic motion of \('P'.\) The restoration force per unit mass when \(P\) touches \(M\) will be ...... \(N\)

  1. A \(100\)
  2. B \(0.49\)
  3. C \(50\)
  4. D \(9.87\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(9.87\)

Step-by-step Solution

Detailed explanation

\(30^{\circ} \rightarrow 0.1\, s\) \(360^{\circ} \rightarrow 1.2 \,s = T\) \(\omega=\frac{2 \pi}{ T }=\frac{5 \pi}{3}\) At \(M , F = m \omega^{2}\, A \Rightarrow \frac{ F }{ m }=\omega^{2}\, A\)
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