JEE Mains · Physics · STD 11 - Oscillations
- JEE Mains 2021
- Hard
- Numerical
Time period of a simple pendulum is \(T\). The time taken to complete \(5 / 8\) oscillations starting from mean position is \(\frac{\alpha}{\beta} T\). The value of \(\alpha\) is ..... .
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(7\)
Step-by-step Solution
Detailed explanation
\(\frac{5}{8}\) th of oscillation \(=\left(\frac{1}{2}+\frac{1}{8}\right)^{\text {th }}\) of oscillation
\(\pi+\theta=\omega t\)
\(\pi+\frac{\pi}{6}=\left(\frac{2 \pi}{T}\right) t\)
\(\frac{7 \pi}{6}=\left(\frac{2 \pi}{T}\right) t\)
\(t=\frac{7 T}{12}\)
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