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JEE Mains · Physics · STD 11 - Oscillations
  • JEE Mains 2021
  • Hard
  • Numerical

Time period of a simple pendulum is \(T\). The time taken to complete \(5 / 8\) oscillations starting from mean position is \(\frac{\alpha}{\beta} T\). The value of \(\alpha\) is ..... .

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Correct Answer

(C) \(7\)

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Detailed explanation

\(\frac{5}{8}\) th of oscillation \(=\left(\frac{1}{2}+\frac{1}{8}\right)^{\text {th }}\) of oscillation

\(\pi+\theta=\omega t\)

\(\pi+\frac{\pi}{6}=\left(\frac{2 \pi}{T}\right) t\)

\(\frac{7 \pi}{6}=\left(\frac{2 \pi}{T}\right) t\)

\(t=\frac{7 T}{12}\)

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