JEE Mains · Physics · STD 11 - 13. oscillations
Time period of a simple pendulum is \(T\). The time taken to complete \(5 / 8\) oscillations starting from mean position is \(\frac{\alpha}{\beta} T\). The value of \(\alpha\) is ..... .
- A \(5\)
- B \(3\)
- C \(7\)
- D \(6\)
Answer & Solution
Correct Answer
(C) \(7\)
Step-by-step Solution
Detailed explanation
\(\frac{5}{8}\) th of oscillation \(=\left(\frac{1}{2}+\frac{1}{8}\right)^{\text {th }}\) of oscillation \(\pi+\theta=\omega t\) \(\pi+\frac{\pi}{6}=\left(\frac{2 \pi}{T}\right) t\) \(\frac{7 \pi}{6}=\left(\frac{2 \pi}{T}\right) t\) \(t=\frac{7 T}{12}\)
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