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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2023
  • Hard
  • MCQ

As shown in the figure, a network of resistors is connected to a battery of \(2\,V\) with an internal resistance of \(3\,\Omega\). The currents through the resistors \(R_4\) and \(R_5\) are \(I_4\) and \(I_5\) respectively. The values of \(I_4\) and \(I_5\) are :

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Answer & Solution

Correct Answer

(D) \(I _4=\frac{2}{5} A\) and \(I _5=\frac{8}{5}\,A\)

Step-by-step Solution

Detailed explanation

Equivalent resistance of circuit

\(R _{ eq } =3+1+2+4+2\)

\(=12 \Omega\)

Current through battery \(i =\frac{24}{12}=2 A\)

\(I _4=\frac{ R _5}{ R _4+ R _5} \times 2=\frac{5}{20+5} \times 2=\frac{2}{5} A\)

\(I _5=2-\frac{2}{5}=\frac{8}{5} A\)

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