JEE Mains · Physics · STD 11 - System of particles and rotational motion
- JEE Mains 2020
- Medium
- MCQ
The radius of gyration of a uniform rod of length \(l,\) about an axis passing through a point \(\frac{l}{4}\) away from the centre of the rod, and perpendicular to it, is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(\sqrt{\frac{7}{48}} l\)
Step-by-step Solution
Detailed explanation
\(\mathrm{m} \frac{l^{2}}{12}+\mathrm{m} \frac{l^{2}}{16}=\mathrm{mk}^{2}\)
\(\frac{7 l^{2}}{48}=k^{2}\)
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