JEE Mains · Physics · STD 11 - Units,dimensions and measurement
- JEE Mains 2022
- Hard
- Numerical
The one division of main scale of vernier callipers reads \(1\,mm\) and \(10\) divisions of Vernier scale is equal to the \(9\) divisions on main scale. When the two jaws of the instrument touch each other the \(zero\) of the Vernier lies to the right of \(zero\) of the main scale and its fourth division coincides with a main scale division. When a spherical bob is tightly placed between the two jaws, the \(zero\) of the Vernier scale lies in between \(4.1\,cm\) and \(4.2\,cm\) and \(6^{\text {th }}\) Vernier division coincides with a main scale division. The diameter of the bob will be \(.............10^{-2}\,cm\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(412\)
Step-by-step Solution
Detailed explanation
\(10\,VSD =9\,MSD\)
\(1\,VST =.9\,MSD\)
\(L.C.\) \(=1\,mm =.01\,cm\)
\(+ve\) zero error \(=4\,mm\)
\(=0.04\,cm\)
Negative zero error \(=4.1\,cm +6 \times .01\)
\(=4.12\,cm\)
\(=412 \times 10^{-2}\,cm\)
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