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JEE Mains · Physics · STD 11 - Friction
  • JEE Mains 2023
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  • MCQ

A body of mass \(10\,kg\) is moving with an initial speed of \(20\,m / s\). The body stops after \(5\,s\) due to friction between body and the floor. The value of the coefficient of friction is (Take acceleration due to gravity \(g =10\; ms ^{-2}\))

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Answer & Solution

Correct Answer

(D) \(0.4\)

Step-by-step Solution

Detailed explanation

\(a=-\mu g\)

\(\because v=u+a t\)

\(0=20+(-\mu \times 10) \times 5\)

\(50 \mu=20\)

\(\mu=\frac{2}{5}=0.4\)

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