JEE Mains · Physics · STD 11 - Friction
- JEE Mains 2023
- Medium
- MCQ
A body of mass \(10\,kg\) is moving with an initial speed of \(20\,m / s\). The body stops after \(5\,s\) due to friction between body and the floor. The value of the coefficient of friction is (Take acceleration due to gravity \(g =10\; ms ^{-2}\))
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(0.4\)
Step-by-step Solution
Detailed explanation
\(a=-\mu g\)
\(\because v=u+a t\)
\(0=20+(-\mu \times 10) \times 5\)
\(50 \mu=20\)
\(\mu=\frac{2}{5}=0.4\)
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