JEE Mains · Physics · STD 12 - Electric potential and capacitance
- JEE Mains 2018
- Hard
- MCQ
Three concentric metal shells \(A, B\) and \(C\) of respective radii \(a, b\) and \(c (a < b < c)\) have surface charge densities \(+\sigma,-\sigma\) and \(+\sigma\) respectively. The potential of shell \(B\) is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(\frac{\sigma}{\epsilon_0} \left[ {\frac{a^2-b^2}{b}+c} \right ]\)
Step-by-step Solution
Detailed explanation
Potential outside the shell, \(V_{outside}\) \(=\frac{\mathrm{KQ}}{\mathrm{r}}\)
where \(\mathrm{r}\) is distance of point from the centre of shel Potential inside the shell, \(V_{\text {inside }}=\frac{K Q}{R}\)
where \('R"\) is radius of the shell
\(\mathrm{V}_{\mathrm{B}}=\frac{\mathrm{Kq}_{\mathrm{A}}}{\mathrm{r}_{\mathrm{b}}}+\frac{\mathrm{Kq}_{\mathrm{B}}}{\mathrm{r}_{\mathrm{b}}}+\frac{\mathrm{Kq}_{\mathrm{C}}}{\mathrm{r}_{\mathrm{c}}}\)
\(\mathrm{V}_{\mathrm{B}}=\frac{1}{4 \pi \epsilon_{0}}\left[\frac{\sigma 4 \pi \mathrm{a}^{2}}{\mathrm{b}}-\frac{\sigma 4 \pi \mathrm{b}^{2}}{\mathrm{b}}+\frac{\sigma 4 \pi \mathrm{c}^{2}}{\mathrm{c}}\right]\)
\(V_{B}=\frac{\sigma}{\epsilon_{0}}\left[\frac{a^{2}-b^{2}}{b}+c\right]\)
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