JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
The value of power dissipated across the zener diode \(\left( V _{ z }=15 V \right)\) connected in the circuit as shown in the figure is \(x \times 10^{-1}\) watt. The value of \(x ,\) to the nearest integer, is ..............
- A \(5\)
- B \(4\)
- C \(2\)
- D \(6\)
Answer & Solution
Correct Answer
(A) \(5\)
Step-by-step Solution
Detailed explanation
Voltage across \(R _{ S }=22-15=7 V\) Current through \(R _{ S }= I =\frac{7}{35}=\frac{1}{5} A\) Current through \(90 \Omega= I _{2}=\frac{15}{90}=\frac{1}{6} A\) Current through zener \(=\frac{1}{5}-\frac{1}{6}=\frac{1}{30} A\) Power through zener diode \(P = VI\)…
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