JEE Mains · Physics · STD 12 - 10. Wave optics
Consider a tank made of glass (refractive index \(1.5\)) with a thick bottom. It is filled with a liquid of refractive index \(\mu \). A student finds that, irrespective of what the incident angle \(I\) (see figure) is for a beam of light entering the liquid, the light reflected from the liquid glass interface is never completely polarized. For this to happen, the minimum value of \(\mu \) is

- A \(\sqrt {\frac{5}{3}} \)
- B \(\frac{3}{{\sqrt 5 }}\)
- C \(\frac{5}{{\sqrt 3 }}\)
- D \(\frac{4}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac{3}{{\sqrt 5 }}\)
Step-by-step Solution
Detailed explanation
\(\sin 90^{\circ}=\mu \sin \theta\) \(\Rightarrow \quad \sin \theta=\frac{1}{\mu}\) \({\mu \sin \theta=1.5 \sin r}\) \({\mu \tan \theta=1.5}\) \( \Rightarrow \tan \theta = \frac{{1.5}}{\mu }\) \(\sin \theta = \frac{3}{{\sqrt {9 + 4{\mu ^2}} }} = \frac{1}{\mu }\)…
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