ExamBro
ExamBro
JEE Mains · Physics · STD 11 - Thermodynamics
  • JEE Mains 2021
  • Medium
  • Numerical

A Carnot's engine working between \(400\, K\) and \(800\, K\) has a work output of \(1200\, J\) per cycle. The amount of heat energy supplied to the engine from the source in each cycle is ........... \(J\)

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(D) \(2400\)

Step-by-step Solution

Detailed explanation

\(\eta=\frac{ T _{2}}{ T _{1}}=\frac{ Q _{2}}{ Q _{1}}=\frac{ Q _{1}- W }{ Q _{1}} \quad\left(\because W = Q _{1}- Q _{2}\right)\)

\(\frac{400}{800}=1-\frac{ W }{ Q _{1}}\)

\(\frac{ W }{ Q _{1}}=1-\frac{1}{2}=\frac{1}{2}\)

\(Q _{1}=2 W =2400 J\)

Same subject
Explore more questions on app