JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
A capacitance of \(2\ μF\) is required in an electrical circuit across a potential difference of \(1.0\ kV\). A large number of \(1\ μF\) capacitors are available which can withstand a potential difference of not more than \(300\ V\). The minimum number of capacitors required to achieve this is
- A \(1\)
- B \(16\)
- C \(24\)
- D \(32\)
Answer & Solution
Correct Answer
(D) \(32\)
Step-by-step Solution
Detailed explanation
To get a capacitance of \(2\, \mu \mathrm{F}\) arrangement of capacitors of capacitance \(1\, \mu \mathrm{F}\) as shown in figure \(8\) capacitors of \(1\, \mu \mathrm{F}\) in parallel with four such branches in series i.e., \(32\) such capacitors are required.…
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