ExamBro
ExamBro
JEE Mains · Physics · STD 12 - Electric potential and capacitance
  • JEE Mains 2017
  • Medium
  • Numerical

A capacitance of \(2\ μF\) is required in an electrical circuit across a potential difference of \(1.0\ kV\). A large number of \(1\ μF\) capacitors are available which can withstand a potential difference of not more than \(300\ V\). The minimum number of capacitors required to achieve this is

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(D) \(32\)

Step-by-step Solution

Detailed explanation

To get a capacitance of \(2\, \mu \mathrm{F}\) arrangement of capacitors of capacitance \(1\, \mu \mathrm{F}\) as shown in figure \(8\) capacitors of \(1\, \mu \mathrm{F}\) in parallel with four such branches in series i.e., \(32\) such capacitors are required.

\(\frac{1}{C_{e q}}=\frac{1}{8}+\frac{1}{8}+\frac{1}{8}+\frac{1}{8} \quad \therefore C_{e q}=2\, \mu F\)

Same subject
Explore more questions on app