JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
A solid sphere of mass \(M\) and radius \(R\) is divided into two unequal parts. The smaller part having mass \(M/8\) is converted into a sphere of radius \(r\) and the larger part is converted into a circular disc of thickness \(t\) and radius \(2R\). If \(I_1\) is moment of inertia of a sphere having radius \(r\) about an axis through its centre and \(I_2\) is the moment of inertia of a disc about its diameter, the ratio of their moment of inertia \(I_2/I_1 = \) _____.
- A \(35\)
- B \(70\)
- C \(140\)
- D \(210\)
Answer & Solution
Correct Answer
(B) \(70\)
Step-by-step Solution
Detailed explanation
Let the mass of the original solid sphere be \(M\) and its radius be \(R\). Mass of the smaller sphere, \(m_1 = \dfrac{M}{8}\). Since the material remains the same, the density is constant. The volume is directly proportional to the mass.…
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