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JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2021
  • Hard
  • Numerical

The circuit contains two diodes each with a forward resistance of \(50\, \Omega\) and with infinite reverse resistance. If the battery voltage is \(6\, V\), the current through the \(120\, \Omega\) resistance is \(mA\)

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Answer & Solution

Correct Answer

(A) \(20\)

Step-by-step Solution

Detailed explanation

In this circuit \(D _{1}\) will be forward bias and \(D _{2}\) will be revers bias.

\(\therefore\) There will be no current through \(D _{2}\) and \(R _{2}\)

Apply \(KVL\) in circuit we get \(+6-50 i -130 i -120 i =0\)

\(i =\frac{6}{300} A =\frac{6}{300} \times 1000 mA\)

\(\Rightarrow 20 mA\)

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