JEE Mains · Physics · STD 12 - Semicondutor electronics
- JEE Mains 2021
- Hard
- Numerical
The circuit contains two diodes each with a forward resistance of \(50\, \Omega\) and with infinite reverse resistance. If the battery voltage is \(6\, V\), the current through the \(120\, \Omega\) resistance is \(mA\)

Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(20\)
Step-by-step Solution
Detailed explanation
In this circuit \(D _{1}\) will be forward bias and \(D _{2}\) will be revers bias.
\(\therefore\) There will be no current through \(D _{2}\) and \(R _{2}\)
Apply \(KVL\) in circuit we get \(+6-50 i -130 i -120 i =0\)
\(i =\frac{6}{300} A =\frac{6}{300} \times 1000 mA\)
\(\Rightarrow 20 mA\)
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