JEE Mains · Physics · STD 11 - 11. thermodynamics
The volume \(V\) of a given mass of monoatomic gas changes with temperature \(T\) according to the relation \(V = KT ^{2 / 3}\). The workdone when temperature changes by \(90\, K\) will be \(x\,R\). The value of \(x\) is \([ R =\) universal gas constant \(]\)
- A \(50\)
- B \(60\)
- C \(48\)
- D \(72\)
Answer & Solution
Correct Answer
(B) \(60\)
Step-by-step Solution
Detailed explanation
We know that work done is \(W =\int PdV\quad \ldots (1)\) \(\Rightarrow P=\frac{ nRT }{ V }\quad \ldots (2)\) \(\Rightarrow W =\int \frac{ nRT }{ V } dv\quad \ldots (3)\) and \(V = KT ^{2 . / 3}\quad \ldots (4)\)…
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