JEE Mains · Physics · STD 11 - 2. motion in straight line
The velocity (\(v\)) versus time (\(t\)) plot of a particle is shown in the figure, for a time interval of \(40\text{ s}\). The total distance travelled by the particle and the average velocity during this period are, respectively _______.
- A \(25\text{ m}\) and zero
- B \(50\text{ m}\) and zero
- C \(100\text{ m}\) and zero
- D \(100\text{ m}\) and \(2.5\text{ m/s}\)
Answer & Solution
Correct Answer
(C) \(100\text{ m}\) and zero
Step-by-step Solution
Detailed explanation
The total distance travelled by the particle is equal to the sum of the magnitudes of the areas under the velocity-time graph. Area of the first triangle (from \(t = 0\) to \(t = 20\text{ s}\)) is: \(A_1 = \dfrac{1}{2} \times 20 \times 5 = 50\text{ m}\) Magnitude of the area of…
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