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JEE Mains · Physics · STD 12 -Alternating current
  • JEE Mains 2024
  • Hard
  • Numerical

A alternating current at any instant is given by \(i=\left[6+\sqrt{56} \sin \left(100 \pi t+\frac{\pi}{3}\right)\right] A\). The rms value of the current is _________ A.

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Answer & Solution

Correct Answer

(D) \(8\)

Step-by-step Solution

Detailed explanation

\(I_{\text {rms }}=\sqrt{\frac{\int i^2 d t}{\int d t}}\)

\(I_{\text {rms }}=\sqrt{(6)^2+\frac{(\sqrt{56})^2}{2}}\)

\(=\sqrt{36+28}\)

\(=\sqrt{64}\)

\(=8 \mathrm{~A}\)

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