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JEE Mains · Physics · STD 11- 8. mechanical properties of solids
Two separate wires \(A\) and \(B\) are stretched by \(2 \,mm\) and \(4\, mm\) respectively, when they are subjected to a force of \(2\, N\). Assume that both the wires are made up of same material and the radius of wire \(B\) is 4 times that of the radius of wire \(A\). The length of the wires \(A\) and \(B\) are in the ratio of \(a : b\). Then \(a / b\) can be expressed as \(1 / x\) where \(x\) is
- A \(24\)
- B \(36\)
- C \(42\)
- D \(32\)
Answer & Solution
Correct Answer
(D) \(32\)
Step-by-step Solution
Detailed explanation
For \(A \frac{ E }{\pi r ^{2}}= y \frac{2 mm }{ a }\) \(......(1)\) For B \(\frac{ E }{\pi \cdot 16 r ^{2}}= y \frac{4 mm }{ b }\) \(..........(2)\) \(\therefore(1) /(2)\) \(16=\frac{2 b }{4 a }\) \(\frac{ a }{ b }=\frac{1}{32}\) \(=32\)
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