JEE Mains · Physics · STD 12 - 8. Electromagnetic waves
The mean intensity of radiation on the surface of the Sun is about \(10^{8}\,W/m^2.\) The \(rms\) value of the corresponding magnetic field is closet to
- A \(1\,T\)
- B \(10^2\,T\)
- C \(10^{-2}\,T\)
- D \(10^{-4}\,T\)
Answer & Solution
Correct Answer
(D) \(10^{-4}\,T\)
Step-by-step Solution
Detailed explanation
\(\mathrm{I}=\frac{\mathrm{B}_{\mathrm{o}}^{2}}{2 \mu_{\mathrm{o}}} \times \mathrm{C}\) \(B_{0}^{2}=1 \times 2 \mu_{0} \times C\) \(B_{0}^{2}=\frac{10^{3} \times 2 \times 4 \pi \times 10^{-7}}{3 \times 10^{8}}\) \(B_{0} \approx 10^{-4} \,T\)
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