ExamBro
ExamBro
JEE Mains · Physics · STD 11 - 9.1 fluid mechanics

The velocity of a small ball of mass \(0.3\,g\) and density \(8\,g / cc\) when dropped in a container filled with glycerine becomes constant after some time. If the density of glycerine is \(1.3\,g / cc\), then the value of viscous force acting on the ball will be \(x \times 10^{-4}\,N\), the value of \(x\) is [use \(g=10\,m / s ^{2}\) ] 

  1. A \(24.125\)
  2. B \(23.125\)
  3. C \(25.125\)
  4. D \(22.125\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(25.125\)

Step-by-step Solution

Detailed explanation

\(F _{ V }+ F _{ B }= mg ( v =\) constant \()\) \(F _{ V }= mg - F _{ B }\) \(=\rho_{ B } Vg -\rho_{ L } Vg\) \(=\left(\rho_{ B }-\rho_{ L }\right) Vg\) \(=(8-1.3) \times 10^{+3} \times \frac{0.3 \times 10^{-3}}{8 \times 10^{3}} \times 10\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app