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JEE Mains · Physics · STD 12 - Nuclei
  • JEE Mains 2023
  • Medium
  • Numerical

A radioactive nucleus decays by two different process. The half life of the first process is \(5\) minutes and that of the second process is \(30\,s\). The effective half-life of the nucleus is calculated to be \(\frac{\alpha}{11}\,s\). The value of \(\alpha\) is \(..............\)

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Answer & Solution

Correct Answer

(C) \(300\)

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Detailed explanation

\(\frac{ dN _1}{ dt }=-\lambda_1 N \quad \frac{ dN _2}{ dt }=-\lambda_2 N\)

\(\frac{ dN }{ dt }=-\left(\lambda_1+\lambda_2\right) N\)

\(\Rightarrow \lambda_{\text {eq }}=\lambda_1+\lambda_2\)

\(\Rightarrow \frac{1}{t_{1 / 2}}=\frac{1}{300}+\frac{1}{30}=\frac{11}{300}\)

\(\Rightarrow t _{1 / 2}=\frac{300}{11}\)

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