JEE Mains · Physics · STD 12 - Nuclei
- JEE Mains 2023
- Medium
- Numerical
A radioactive nucleus decays by two different process. The half life of the first process is \(5\) minutes and that of the second process is \(30\,s\). The effective half-life of the nucleus is calculated to be \(\frac{\alpha}{11}\,s\). The value of \(\alpha\) is \(..............\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(300\)
Step-by-step Solution
Detailed explanation
\(\frac{ dN _1}{ dt }=-\lambda_1 N \quad \frac{ dN _2}{ dt }=-\lambda_2 N\)
\(\frac{ dN }{ dt }=-\left(\lambda_1+\lambda_2\right) N\)
\(\Rightarrow \lambda_{\text {eq }}=\lambda_1+\lambda_2\)
\(\Rightarrow \frac{1}{t_{1 / 2}}=\frac{1}{300}+\frac{1}{30}=\frac{11}{300}\)
\(\Rightarrow t _{1 / 2}=\frac{300}{11}\)
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