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JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2021
  • Hard
  • Numerical

A zener diode of power rating \(2\, {W}\) is to be used as a voltage regulator. If the zener diode has a breakdown of \(10 \,{V}\) and it has to regulate voltage fluctuated between \(6\, {V}\) and \(14\, {V}\), the value of \({R}_{{s}}\) for safe operation should be \(....\Omega\)

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Answer & Solution

Correct Answer

(B) \(20\)

Step-by-step Solution

Detailed explanation

When unregulated voltage is \(14\, {V}\) voltage across

zener diode must be \(10\, {V}\) So potential difference

across resistor \(\Delta {V}_{{Rs}}=4\, {V}\)

and \({P}_{\text {zener }}=2\, {W}\)

\({VI}=2\)

\({I}=\frac{2}{10}=0.2\, {A}\)

\(\Delta {V}_{{Rs}}={I} {R}_{{s}}\)

\(4 \times 0.2 {R}_{s} \Rightarrow {R}_{5}=\frac{40}{2}=20\, \Omega\)

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