JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
A zener diode of power rating \(2\, {W}\) is to be used as a voltage regulator. If the zener diode has a breakdown of \(10 \,{V}\) and it has to regulate voltage fluctuated between \(6\, {V}\) and \(14\, {V}\), the value of \({R}_{{s}}\) for safe operation should be \(....\Omega\)

- A \(10\)
- B \(20\)
- C \(15\)
- D \(25\)
Answer & Solution
Correct Answer
(B) \(20\)
Step-by-step Solution
Detailed explanation
When unregulated voltage is \(14\, {V}\) voltage across zener diode must be \(10\, {V}\) So potential difference across resistor \(\Delta {V}_{{Rs}}=4\, {V}\) and \({P}_{\text {zener }}=2\, {W}\) \({VI}=2\) \({I}=\frac{2}{10}=0.2\, {A}\) \(\Delta {V}_{{Rs}}={I} {R}_{{s}}\)…
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