JEE Mains · Physics · STD 11 - Newtons laws of motion
- JEE Mains 2021
- Hard
- Numerical
Consider a frame that is made up of two thin massless rods \(AB\) and \(AC\) as shown in the figure. \(A\) vertical force \(\overrightarrow{ P }\) of magnitude \(100 \;N\) is applied at point \(A\) of the frame. Suppose the force is \(\overrightarrow{ P }\) resolved parallel to the arms \(AB\) and \(AC\) of the frame. The magnitude of the resolved component along the arm \(AC\) is \(xN\). The value of \(x\), to the nearest integer, is ............ [Given : \(\sin \left(35^{\circ}\right)=0.573, \cos \left(35^{\circ}\right)=0.819\) \(\left.\sin \left(110^{\circ}\right)=0.939, \cos \left(110^{\circ}\right)=-0.342\right]\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(82\)
Step-by-step Solution
Detailed explanation
Component along \(AC\)
\(=100 \cos 35^{\circ} N\)
\(=100 \times 0.819 N\)
\(=81.9 N\)
\(\approx 82 N\)
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