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JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion

Consider a frame that is made up of two thin massless rods \(AB\) and \(AC\) as shown in the figure. \(A\) vertical force \(\overrightarrow{ P }\) of magnitude \(100 \;N\) is applied at point \(A\) of the frame. Suppose the force is \(\overrightarrow{ P }\) resolved parallel to the arms \(AB\) and \(AC\) of the frame. The magnitude of the resolved component along the arm \(AC\) is \(xN\). The value of \(x\), to the nearest integer, is ............ [Given : \(\sin \left(35^{\circ}\right)=0.573, \cos \left(35^{\circ}\right)=0.819\) \(\left.\sin \left(110^{\circ}\right)=0.939, \cos \left(110^{\circ}\right)=-0.342\right]\)  

  1. A \(82\)
  2. B \(72\)
  3. C \(87\)
  4. D \(78\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(82\)

Step-by-step Solution

Detailed explanation

Component along \(AC\) \(=100 \cos 35^{\circ} N\) \(=100 \times 0.819 N\) \(=81.9 N\) \(\approx 82 N\)
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