JEE Mains · Physics · STD 12 - 3. current electricity
The voltage drop across \(15\, \Omega\) resistance in the given figure will be \(.....V.\)
- A \(8\)
- B \(60\)
- C \(6\)
- D \(9\)
Answer & Solution
Correct Answer
(C) \(6\)
Step-by-step Solution
Detailed explanation
Point drop across \(6 \,\Omega=1 \times 6=6={V}_{{AB}}\) \(\Rightarrow\) Hence point drop across \(15 \,\Omega=6\) \(volt\) \(={V}_{{AB}}\)
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