JEE Mains · Physics · STD 12 -6. Electromagnetic induction
A square frame of side \(10\, cm\) and a long straight wire carrying current \(1\, A\) are in the plate of the paper. Starting from close to the wire, the frame moves towards the right with a constant speed of \(10\, ms^{-1}\) (see figure). The \(e.m. f\) induced at the time the left arm of the frame is at \(x\, = 10\, cm\) from the wire is .....\(\mu V\)
- A \(2\)
- B \(1\)
- C \(0.75\)
- D \(0.5\)
Answer & Solution
Correct Answer
(B) \(1\)
Step-by-step Solution
Detailed explanation
In the given question, Current flowing through the wire, \(I=1\, A\) Speed of the frame, \(\mathrm{v}=10\, \mathrm{ms}^{-1}\) Side of square loop, \(l=10\, \mathrm{cm}\) Distance of square frame from current carrying wires \(x=10\, \mathrm{cm}\) We have to find, \(e.m.f\)…
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