JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
The velocity at which \(6\) kg mass (shown in figure) strikes the ground when it is released from a height of \(6\) m above the ground is __________ m/s. Assume pulley is massless and string is light and inextensible. (Take g \(= 10\) m/s\(^2\))
- A \(7.74\)
- B \(7.20\)
- C \(6.55\)
- D \(4.50\)
Answer & Solution
Correct Answer
(A) \(7.74\)
Step-by-step Solution
Detailed explanation
Let the acceleration of the system be \(a\) and the tension in the string be \(T\). The equations of motion for the two masses are: \(6g - T = 6a\) \(T - 2g = 2a\) Adding the two equations, we get: \(4g = 8a\) \(\Rightarrow a = \dfrac{4g}{8} = \dfrac{g}{2}\) Substituting…
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