JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
Concentric metallic hollow spheres of radii \(R\) and \(4 R\) hold charges \(Q _{1}\) and \(Q _{2}\) respectively. Given that surface charge densities of the concentric spheres are equal, the potential difference \(V ( R )- V (4 R )\) is
- A \(\frac{3 Q_{1}}{16 \pi \varepsilon_{0} R}\)
- B \(\frac{ Q _{2}}{4 \pi \varepsilon_{0} R }\)
- C \(\frac{3 Q _{1}}{4 \pi \varepsilon_{0} R }\)
- D \(\frac{3 Q _{2}}{4 \pi \varepsilon_{0} R }\)
Answer & Solution
Correct Answer
(A) \(\frac{3 Q_{1}}{16 \pi \varepsilon_{0} R}\)
Step-by-step Solution
Detailed explanation
\(E =\frac{ KQ _{1}}{ r ^{2}}\) \(\Delta V =\int_{ R }^{4 R } E dr =\frac{3 KQ _{1}}{4 R }\)
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