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JEE Mains · Physics · STD 12 -Alternating current
  • JEE Mains 2024
  • Hard
  • MCQ

\(LCR\) circuit is at resonance for a capacitor \(C\), inductance \(L\) and resistance \(R\). Now the value of resistance is halved keeping all other parameters same. The current amplitude at resonance will be now what?

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Answer & Solution

Correct Answer

(B) double

Step-by-step Solution

Detailed explanation

In resonance \(Z=R\)

\(\mathrm{I}=\frac{\mathrm{V}}{\mathrm{R}}\)

\(\mathrm{R} \rightarrow \text { halved }\)

\(\Rightarrow \mathrm{I} \rightarrow 2 \mathrm{I}\)

I becomes doubled.

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