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JEE Mains · Physics · STD 11 - Kinetic theory of gases
  • JEE Mains 2018
  • Hard
  • Numerical

Two moles of helium are mixed with \(n\)  with moles of hydrogen. If \(\frac{{{C_P}}}{{{C_V}}}\, = \,\frac{3}{2}\)  for the mixture, then the value of \(n\)  is

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Answer & Solution

Correct Answer

(B) \(2\)

Step-by-step Solution

Detailed explanation

Using formula,

\({\gamma _{mixture}} = {\left( {\frac{{{C_p}}}{{{C_V}}}} \right)_{mix}} = \frac{{\frac{{{n_1}{\gamma _1}}}{{{\gamma _1} - 1}} + \frac{{{n_2}{\gamma _2}}}{{{\gamma _2} - 1}}}}{{\frac{{{n_1}}}{{{\gamma _1} - 1}} + \frac{{{n_2}}}{{{\gamma _2} - 1}}}}\)

Putting the value of \({n_1} = 2,{n_2} = n.\)

\({\left( {\frac{{{C_p}}}{{{C_v}}}} \right)_{mix }} = \frac{3}{2}\)

\({\gamma _1} = \frac{5}{3},{\gamma _2} = \frac{7}{5}\) and solving we get, \(n=2\)

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