JEE Mains · Physics · STD 11 - Kinetic theory of gases
- JEE Mains 2018
- Hard
- Numerical
Two moles of helium are mixed with \(n\) with moles of hydrogen. If \(\frac{{{C_P}}}{{{C_V}}}\, = \,\frac{3}{2}\) for the mixture, then the value of \(n\) is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
Using formula,
\({\gamma _{mixture}} = {\left( {\frac{{{C_p}}}{{{C_V}}}} \right)_{mix}} = \frac{{\frac{{{n_1}{\gamma _1}}}{{{\gamma _1} - 1}} + \frac{{{n_2}{\gamma _2}}}{{{\gamma _2} - 1}}}}{{\frac{{{n_1}}}{{{\gamma _1} - 1}} + \frac{{{n_2}}}{{{\gamma _2} - 1}}}}\)
Putting the value of \({n_1} = 2,{n_2} = n.\)
\({\left( {\frac{{{C_p}}}{{{C_v}}}} \right)_{mix }} = \frac{3}{2}\)
\({\gamma _1} = \frac{5}{3},{\gamma _2} = \frac{7}{5}\) and solving we get, \(n=2\)
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