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JEE Mains · Physics · STD 12 -Alternating current
  • JEE Mains 2023
  • Easy
  • Numerical

An \(LCR\) series circuit of capacitance \(62.5\,nF\) and resistance of \(50\,\Omega\). is connected to an \(A.C.\) source of frequency \(2.0\,kHz\). For maximum value of amplitude of current in circuit, the value of inductance is \(..........mH\). (take \(\left.\pi^2=10\right)\)

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Answer & Solution

Correct Answer

(D) \(100\)

Step-by-step Solution

Detailed explanation

\(f =\frac{1}{2 \pi \sqrt{ LC }}\)

\(2000\,Hz =\frac{1}{2 \pi \sqrt{ L \times 62.5 \times 10^{-9}}}\)

\(L =\frac{1}{4 \pi^2 \times 2000^2 \times 62.5 \times 10^{-9}}=0.1\,H =100\,mH\)

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