JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
The truth of the given circuit diagram is _______.

- A
\(A\) \(B\) \(y\) \(0\) \(0\) \(1\) \(0\) \(1\) \(0\) \(1\) \(0\) \(0\) \(1\) \(1\) \(1\) - B
\(A\) \(B\) \(y\) \(0\) \(0\) \(0\) \(0\) \(1\) \(1\) \(1\) \(0\) \(1\) \(1\) \(1\) \(0\) - C
\(A\) \(B\) \(y\) \(0\) \(0\) \(0\) \(0\) \(1\) \(0\) \(1\) \(0\) \(0\) \(1\) \(1\) \(1\) - D
\(A\) \(B\) \(y\) \(0\) \(0\) \(1\) \(0\) \(1\) \(1\) \(1\) \(0\) \(1\) \(1\) \(1\) \(0\)
Answer & Solution
Correct Answer
(B) \(A\) \(B\) \(y\) \(0\) \(0\) \(0\) \(0\) \(1\) \(1\) \(1\) \(0\) \(1\) \(1\) \(1\) \(0\)
Step-by-step Solution
Detailed explanation
\(\mathrm{Y}=\mathrm{A} \cdot \overline{\mathrm{B}}+\overline{\mathrm{A}} \cdot \mathrm{B}\) This is \(XOR\) \(GATE\)
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