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JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases

The temperature of a gas having \(2.0 \times 10^{25}\) molecules per cubic meter at \(1.38 \mathrm{~atm}\) (Given, \(\mathrm{k}=\) \(\left.1.38 \times 10^{-23} \mathrm{JK}^{-1}\right)\) is _______.

  1. A \(500 \mathrm{~K}\)
  2. B \(200 \mathrm{~K}\)
  3. C \(100 \mathrm{~K}\)
  4. D \(300 \mathrm{~K}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(500 \mathrm{~K}\)

Step-by-step Solution

Detailed explanation

\( \mathrm{PV}=\mathrm{nRT} \) \( \mathrm{PV}=\frac{\mathrm{N}}{\mathrm{N}_{\mathrm{A}}} \mathrm{RT}\) \(\mathrm{N}=\) Total no. of molecules \(\mathrm{P}=\frac{\mathrm{N}}{\mathrm{V}} \mathrm{kT}\)…
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