JEE Mains · Physics · STD 11 - 7. gravitation
A solid sphere of mass \(‘M’\) and radius \(‘a’\) is surrounded by a uniform concentric spherical shell of thickness \(2a\) and mass \(2M.\) The gravitational field at distance \(‘3a’\) from the centre will be
- A \(\frac{{GM}}{{3{a^2}}}\)
- B \(\frac{{2GM}}{{9{a^2}}}\)
- C \(\frac{{GM}}{{9{a^2}}}\)
- D \(\frac{{2GM}}{{3{a^2}}}\)
Answer & Solution
Correct Answer
(A) \(\frac{{GM}}{{3{a^2}}}\)
Step-by-step Solution
Detailed explanation
We use Gauss's Law for gravitation \(g.4\pi {r^2} = \left( {Mass\,enclosed} \right)4\pi G\) \(g = \frac{{3M4\pi G}}{{4\pi {{\left( {3a} \right)}^2}}} = \frac{{GM}}{{3{a^2}}}\)
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