JEE Mains · Physics · STD 12 -7. Alternating current
Match List\(-I\) with List\(-II\) :
| List\(-I\) | List\(-II\) |
| \((a)\) \(\omega L\,>\,\frac{1}{\omega C}\) | \((i)\) Current is in phase with \(emf\) |
| \((b)\) \(\omega {L}=\frac{1}{\omega {C}}\) | \((ii)\) Current lags behind the applied \(emf\) |
| \((c)\) \(\omega {L}\, < \,\frac{1}{\omega {C}}\) | \((iii)\) Maximum current occurs |
| \((d)\) resonant frequency | \((iv)\) Current leads the \(emf\) |
- A \((a) - (iv) ; (b) - (iii) ; (c) - (ii) ; (d) - (i)\)
- B \((a) - (iii) ; (b) - (i) ; (c) - (iv) ; (d) - (ii)\)
- C \((a) - (ii) ; (b) - (i) ; (c) - (iv) ; (d) - (iii)\)
- D \((a) - (ii) ; (b) - (i) ; (c) - (iii) ; (d) - (iv)\)
Answer & Solution
Correct Answer
(C) \((a) - (ii) ; (b) - (i) ; (c) - (iv) ; (d) - (iii)\)
Step-by-step Solution
Detailed explanation
\((a)\) For \({x}_{{L}}\,>\,{x}_{{C}}\), voltage leads the current \((ii)\) \((b)\) For \(x_{L}=x_{C}\), voltage \(\&\) current are in same phase \((i)\) \((c)\) For \({x}_{{L}}\, < \,{x}_{{C}}\), current leads the voltage \((iv)\) \((d)\) For resonant frequency…
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