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JEE Mains · Physics · STD 12 -7. Alternating current

Match List\(-I\) with List\(-II\) :
List\(-I\) List\(-II\)
\((a)\) \(\omega L\,>\,\frac{1}{\omega C}\) \((i)\) Current is in phase with \(emf\)
\((b)\) \(\omega {L}=\frac{1}{\omega {C}}\) \((ii)\) Current lags behind the applied \(emf\)
\((c)\) \(\omega {L}\, < \,\frac{1}{\omega {C}}\) \((iii)\) Maximum current occurs
\((d)\) resonant frequency \((iv)\) Current leads the \(emf\)
Choose the correct answer from the options given below :

  1. A \((a) - (iv) ; (b) - (iii) ; (c) - (ii) ; (d) - (i)\)
  2. B \((a) - (iii) ; (b) - (i) ; (c) - (iv) ; (d) - (ii)\)
  3. C \((a) - (ii) ; (b) - (i) ; (c) - (iv) ; (d) - (iii)\)
  4. D \((a) - (ii) ; (b) - (i) ; (c) - (iii) ; (d) - (iv)\)
Verified Solution

Answer & Solution

Correct Answer

(C) \((a) - (ii) ; (b) - (i) ; (c) - (iv) ; (d) - (iii)\)

Step-by-step Solution

Detailed explanation

\((a)\) For \({x}_{{L}}\,>\,{x}_{{C}}\), voltage leads the current \((ii)\) \((b)\) For \(x_{L}=x_{C}\), voltage \(\&\) current are in same phase \((i)\) \((c)\) For \({x}_{{L}}\, < \,{x}_{{C}}\), current leads the voltage \((iv)\) \((d)\) For resonant frequency…
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