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JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
  • JEE Mains 2022
  • Medium
  • MCQ

An electron with speed \(v\) and a photon with speed \(c\) have the same \(de-Broglie\) wavelength. If the kinetic energy and momentum of electron are \(E_{ e }\) and \(pe _{ e }\) and that of photon are \(E _{ ph }\) and \(p _{ ph }\) respectively. Which of the following is correct?

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Answer & Solution

Correct Answer

(B) \(\frac{E_{e}}{E_{p h}}=\frac{v}{2 c}\)

Step-by-step Solution

Detailed explanation

\(\lambda_{ e }=\lambda_{\text {photon }}\)

\(\frac{ h }{ mv }=\frac{ h }{ P _{\text {photon}}} \Rightarrow P _{\text {photon }}= mv\)

\(\frac{ E _{ e }}{ E _{ ph }}=\frac{\frac{1}{2} mv ^{2}}{\frac{ hc }{\lambda}}=\frac{1}{2} \frac{ mv }{ P _{ Ph } C } \times v =\frac{ v }{2 C }\)

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