ExamBro
ExamBro
JEE Mains · Physics · STD 11 - 11. thermodynamics

A Carnot freezer takes heat from water at \(0\,^oC\) inside it and rejects it to the room at a temperature of \(27\,^oC\). The latent heat of ice is \(336 \times 10^3\, J\,kg^{-1}\).  lf \(5\, kg\) of water at \(0\,^oC\) is converted into ice at  \(0\,^oC\) by the freezer, then the energy consumed by the freezer is close to

  1. A \(1.51 \times {10^5}\,J\)
  2. B \(1.68 \times {10^6}\,J\)
  3. C \(1.71 \times {10^7}\,J\)
  4. D \(1.67 \times {10^5}\,J\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(1.67 \times {10^5}\,J\)

Step-by-step Solution

Detailed explanation

\(\Delta H = mL = 5 \times 336 \times {10^3} = {Q_{sink}}\) \(\frac{{{Q_{sink}}}}{{{Q_{source}}}} - \frac{{{T_{sink}}}}{{{T_{source}}}}\) \(\therefore {Q_{source}} = \frac{{{T_{source}}}}{{{T_{sink}}}} \times {Q_{sink}}\) Energy consumed by freezer…
Same subject
Explore more questions on app