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JEE Mains · Physics · STD 12 -Alternating current
  • JEE Mains 2021
  • Medium
  • Numerical

A series \(LCR\) circuit is designed to resonate at an angular frequency \(\omega_{0}=10^{5} \,rad / s\). The circuit draws \(16\, W\) power from \(120\, V\) source at resonance. The value of resistance \('R'\) in the circuit is ...... \(\Omega\).

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Answer & Solution

Correct Answer

(D) \(900\)

Step-by-step Solution

Detailed explanation

At resonance

\(P =\frac{ V ^{2}}{ R }\)

\(R =\frac{ V ^{2}}{ P } =\frac{(120)^{2}}{16}\)

\(=900 \,\Omega\)

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