JEE Mains · Physics · STD 12 -Alternating current
- JEE Mains 2021
- Medium
- Numerical
A series \(LCR\) circuit is designed to resonate at an angular frequency \(\omega_{0}=10^{5} \,rad / s\). The circuit draws \(16\, W\) power from \(120\, V\) source at resonance. The value of resistance \('R'\) in the circuit is ...... \(\Omega\).
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(900\)
Step-by-step Solution
Detailed explanation
At resonance
\(P =\frac{ V ^{2}}{ R }\)
\(R =\frac{ V ^{2}}{ P } =\frac{(120)^{2}}{16}\)
\(=900 \,\Omega\)
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