JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
If mass is written as \(\mathrm{m}=\mathrm{kc}^{\mathrm{p}} \mathrm{G}^{-1 / 2} \mathrm{~h}^{1 / 2}\) then the value of \(P\) will be _______. (Constants have their usual meaning with \(\mathrm{k}\) a dimensionless constant)
- A \(1 / 2\)
- B \(1 / 3\)
- C \(2\)
- D \(-1 / 3\)
Answer & Solution
Correct Answer
(A) \(1 / 2\)
Step-by-step Solution
Detailed explanation
\(\mathrm{m}=\mathrm{kc}^{\mathrm{P}} \mathrm{G}^{-1 / 2} \mathrm{~h}^{1 / 2}\)…
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