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JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
- JEE Mains 2022
- Medium
- MCQ
The ratio of wavelengths of proton and deuteron accelerated by potential \(V_{p}\) and \(V_{d}\) is 1: \(\sqrt{2}\). Then, the ratio of \(V_{p}\) to \(V_{d}\) will be
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(4: 1\)
Step-by-step Solution
Detailed explanation
Kinetic energy gained by a charged particle accelerated by a potential \(V\) is \(qV\) \(KE = qV\)
\(\frac{ p ^{2}}{2 m }= qV \Rightarrow p =\sqrt{2 mqV }\)
\(p =\frac{ h }{\lambda}, \text { thus } \lambda=\frac{ h }{\sqrt{2 mqV }}\)
now \(\frac{\lambda_{ p }}{\lambda_{ d }}=\sqrt{\frac{ m _{ d } V _{ d }}{ m _{ p } V _{ p }}}\)
\(\Rightarrow \frac{1}{\sqrt{2}}=\sqrt{\frac{2 V_{d}}{V_{p}}} \Rightarrow \frac{V_{p}}{V_{d}}=4\)
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