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JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
The ratio of wavelengths of proton and deuteron accelerated by potential \(V_{p}\) and \(V_{d}\) is 1: \(\sqrt{2}\). Then, the ratio of \(V_{p}\) to \(V_{d}\) will be
- A \(1: 1\)
- B \(\sqrt{2}: 1\)
- C \(2: 1\)
- D \(4: 1\)
Answer & Solution
Correct Answer
(D) \(4: 1\)
Step-by-step Solution
Detailed explanation
Kinetic energy gained by a charged particle accelerated by a potential \(V\) is \(qV\) \(KE = qV\) \(\frac{ p ^{2}}{2 m }= qV \Rightarrow p =\sqrt{2 mqV }\) \(p =\frac{ h }{\lambda}, \text { thus } \lambda=\frac{ h }{\sqrt{2 mqV }}\) now…
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