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JEE Mains · Physics · STD 11 - Motion in plane
  • JEE Mains 2022
  • Medium
  • MCQ

Given below are two statements. One is labelled as Assertion \(A\) and the other is labelled as Reason \(R\). Assertion A :Two identical balls \(A\) and \(B\) thrown with same velocity '\(u\) ' at two different angles with horizontal attained the same range \(R\). If \(A\) and \(B\) reached the maximum height \(h_{1}\) and \(h_{2}\) respectively, then \(R =4 \sqrt{ h _{1} h _{2}}\) Reason R: Product of said heights. \(h _{1} h _{2}=\left(\frac{u^{2} \sin ^{2} \theta}{2 g }\right) \cdot\left(\frac{u^{2} \cos ^{2} \theta}{2 g }\right)\) Choose the \(CORRECT\) answer 

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Answer & Solution

Correct Answer

(A) Both \(A\) and \(R\) are true and \(R\) is the correct explanation of \(A\).

Step-by-step Solution

Detailed explanation

For same range \(\theta_{1}+\theta_{2}=90^{\circ}\)

\(h _{1} h _{2}=\frac{ u ^{2} \sin ^{2} \theta_{1}}{2 g } \times \frac{ u ^{2} \sin ^{2} \theta_{2}}{2 g }\)

\(\theta_{2}=90-\theta_{1}\)

\(h _{1} h _{2}=\frac{ u ^{2} \sin ^{2} \theta_{1}}{2 g } \cdot \frac{ u ^{2} \cos ^{2} \theta_{1}}{2 g }\)

\(=\left[\frac{ u ^{2} \sin \theta_{1} \cos \theta_{1}}{2 g }\right]^{2}\)

\(=\left[\frac{ u ^{2} \sin \theta_{1} \cos \theta_{1}}{2 g } \times \frac{2}{2}\right]^{2}=\frac{ R ^{2}}{16}\)

\(R =4 \sqrt{ h _{1} h _{2}}\)

So \(R\) is correct explanation of \(A\)

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