JEE Mains · Physics · STD 11 - 3.2 motion in plane
Given below are two statements. One is labelled as Assertion \(A\) and the other is labelled as Reason \(R\). Assertion A :Two identical balls \(A\) and \(B\) thrown with same velocity '\(u\) ' at two different angles with horizontal attained the same range \(R\). If \(A\) and \(B\) reached the maximum height \(h_{1}\) and \(h_{2}\) respectively, then \(R =4 \sqrt{ h _{1} h _{2}}\) Reason R: Product of said heights. \(h _{1} h _{2}=\left(\frac{u^{2} \sin ^{2} \theta}{2 g }\right) \cdot\left(\frac{u^{2} \cos ^{2} \theta}{2 g }\right)\) Choose the \(CORRECT\) answer
- A Both \(A\) and \(R\) are true and \(R\) is the correct explanation of \(A\).
- B Both \(A\) and \(R\) are true but \(R\) is NOT the correct explanation of \(A\).
- C A is true but \(R\) is false
- D A is false but \(R\) is true
Answer & Solution
Correct Answer
(A) Both \(A\) and \(R\) are true and \(R\) is the correct explanation of \(A\).
Step-by-step Solution
Detailed explanation
For same range \(\theta_{1}+\theta_{2}=90^{\circ}\) \(h _{1} h _{2}=\frac{ u ^{2} \sin ^{2} \theta_{1}}{2 g } \times \frac{ u ^{2} \sin ^{2} \theta_{2}}{2 g }\) \(\theta_{2}=90-\theta_{1}\)…
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