JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
- JEE Mains 2023
- Hard
- MCQ
The pressure \(( P )\) and temperature \(( T )\) relationship of an ideal gas obeys the equation \(PT ^2=\) constant. The volume expansion coefficient of the gas will be:
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(\frac{3}{T}\)
Step-by-step Solution
Detailed explanation
\(PT ^2=\text { constant, Using } PV = nRT\)
\(P =\frac{ nRT }{ V } \)
\( PT ^2=\frac{ nRT }{ V } \times T ^2=\text { constant }\)
\(\Rightarrow T ^3= KV \)
\(\text { So, } \frac{ d }{ dT }( KV )=3 T ^2\)
\(\Rightarrow \frac{ KdV }{ dT }=3 T ^2\)
\(\Rightarrow dV =\frac{3 T ^2}{ K } dT\)
\(dV = V \gamma dT \quad \Rightarrow \gamma=\frac{3 T ^2}{ KV ^2}=\frac{3 T ^2}{ T ^3}=\frac{3}{ T }\)
\(\Rightarrow \gamma V =\frac{3 T ^2}{ K }\)
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