JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
The pressure \(( P )\) and temperature \(( T )\) relationship of an ideal gas obeys the equation \(PT ^2=\) constant. The volume expansion coefficient of the gas will be:
- A \(3 T ^2\)
- B \(\frac{3}{ T ^2}\)
- C \(\frac{3}{ T ^3}\)
- D \(\frac{3}{T}\)
Answer & Solution
Correct Answer
(D) \(\frac{3}{T}\)
Step-by-step Solution
Detailed explanation
\(PT ^2=\text { constant, Using } PV = nRT\) \(P =\frac{ nRT }{ V } \) \( PT ^2=\frac{ nRT }{ V } \times T ^2=\text { constant }\) \(\Rightarrow T ^3= KV \) \(\text { So, } \frac{ d }{ dT }( KV )=3 T ^2\) \(\Rightarrow \frac{ KdV }{ dT }=3 T ^2\)…
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