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JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
  • JEE Mains 2023
  • Medium
  • MCQ

The graph between two temperature scales \(P\) and \(Q\) is shown in the figure. Between upper fixed point and lower fixed point there are \(150\) equal divisions of scale \(P\) and \(100\) divisions on scale \(Q\). The relationship for conversion between the two scales is given by :

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Answer & Solution

Correct Answer

(B) \(\frac{t_Q}{100}=\frac{t_P-30}{150}\)

Step-by-step Solution

Detailed explanation

\(\frac{\text { reading on scale }-\text { Lower fixed point }}{\text { upper fixed point }-\text { lower fixed point }}=\text { constant }\)

\(\frac{t_P-30}{180-30}=\frac{t_Q-0}{100-0}\)

\(\frac{t_P-30}{150}=\frac{t_Q}{100}\)

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