JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
Three force \(F_1=10\,N , F_2=8\,N , F _3=6\,N\) are acting on a particle of mass \(5\,kg\). The forces \(F _2\) and \(F _3\) are applied perpendicular so that particle remains at rest. If the force \(F_1\) is removed, then the acceleration of the particle is \(......ms^{-2}\)
- A \(2\)
- B \(0.5\)
- C \(4.8\)
- D \(7\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
Resultant of \(\overrightarrow{ F _2}\) and \(\overrightarrow{ F _3}\) should be opposite to \(\overrightarrow{ F _1}\) \(a=\frac{10}{5}=2\,m / s ^2\)
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