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JEE Mains · Physics · STD 11 - Newtons laws of motion
  • JEE Mains 2023
  • Medium
  • Numerical

Three force \(F_1=10\,N , F_2=8\,N , F _3=6\,N\) are acting on a particle of mass \(5\,kg\). The forces \(F _2\) and \(F _3\) are applied perpendicular so that particle remains at rest. If the force \(F_1\) is removed, then the acceleration of the particle is \(......ms^{-2}\)

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Answer & Solution

Correct Answer

(A) \(2\)

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Detailed explanation

Resultant of \(\overrightarrow{ F _2}\) and \(\overrightarrow{ F _3}\) should be opposite to \(\overrightarrow{ F _1}\)

\(a=\frac{10}{5}=2\,m / s ^2\)

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