JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
A zener diode of power rating \(1.6\,W\) is to be used as voltage regulator. If the zener diode has a breakdown of \(8\,V\) and it has to regulate voltage fluctuating between \(3\,V\) and \(10 \,V\). The value of resistance \(R_5\) for safe operation of diode will be \(.........\Omega\)
- A \(13.3\)
- B \(12\)
- C \(10\)
- D \(13\)
Answer & Solution
Correct Answer
(C) \(10\)
Step-by-step Solution
Detailed explanation
\(V_b=8 \text { volt }\) \(V_A-V_B=8 \text { volt }\) Current through zener diode, \(i =\frac{ P }{ V }=\frac{1.6 W }{8 V }=0.2\,A\) \(V _{ C }- V _{ A }=10-8 \text { volt }\) \(\therefore R =\frac{ V _{ C }- V _{ A }}{ i }=\frac{2 V }{0.2 A }=10\,\Omega\) [Note : A zener diode…
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